Question

A regular hexagon of side 10 cm has a charge $5\mu C$ at each of its vertices. Calculate the potential at the centre of the hexagon.

• A. $5.8\times {10}^{6}V$
• B. $3.2\times {10}^{6}V$
• C. $9.3\times {10}^{6}V$
• D. $2.7\times {10}^{6}V$

Answer 1

The correct option is D $2.7\times {10}^{6}V$

$V={\sum }_{i=1}^{6}k\frac{5\mu c\times 1}{r}$
$r$ is distance of vertex of hexagon from the center,
Thus, $r=10cm$
Therefore,
$V=2.7\times {10}^{6}V$