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Question

A regular hexagonal uniform block of mass m=43 kg rests on a rough horizontal surface with coefficient of friction μ as shown in figure. A constant horizontal force is applied on the block as shown. If the friction is sufficient to prevent slipping before toppling, then the minimum force (in N) required to topple the block about its corner A is
(Take g=10 m/s2)

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Solution

Situation when the hexagonal block is just about to topple. Normal reaction will shift to A (extreme)


Torque balance about point A :
F(2acos30o)=mg(a2)
F(2×a×32)=43×10×a2
F=20 N

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