A regular polygon has 12 sides, find the measure of each of its interior angles.

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Solution

Each interior angle $= (\frac{2 n - 4}{n}) \times 90^{o}$
here $n = 12$
$∴$ Each interior angle $= \frac{2 \times 12 - 4}{12} \times 90^{o}$
$= \frac{20}{12} \times 90^{o} = 150^{o}$

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A regular polygon has 12 sides, find the measure of each of its interior angles.

Each interior angle =(2n−4n)×90ohere n=12∴ Each interior angle =2×12−412×90o=2012×90o=150o

Each interior angle $= (\frac{2 n - 4}{n}) \times 90^{o}$
here $n = 12$
$∴$ Each interior angle $= \frac{2 \times 12 - 4}{12} \times 90^{o}$
$= \frac{20}{12} \times 90^{o} = 150^{o}$