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Question

A relation on the set A=[x:x<3,xϵZ], Where Z, the set of integers, is defined by R=[(x,y):y=x,x1]. Then, the number of elements in the power set of R is

A
32
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B
16
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C
8
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D
64
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Solution

The correct option is B 16
First consider R=[(x,y):y=x,x1]
A={2,1,0,1,2} (since |x|<3 and xZ)
R={(0,0),(1,1),(2,2),(2,2)} (since x1)
There are 4 elements in R.
Power set contains all subsets of a given set.
Hence number of elements in power set of R
=4C0+4C1+4C2+4C3+4C4
=1+4+6+4+1=16.
Alternatively, using the result, No. of elements in power set=2n,
where 'n' is the total number of elements in a set,
we get 24=16.

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