CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A relation R defined on the set of all non-negative integers where, aRb if and only if b=ak for some positive integer k. Then select the corrrect statement(s).

A
Codom(R)={0,1,2,3,4,5,...}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Range(R)={ak:aZ,k>0}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
R={(a,b)W×W:b=ak}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Dom(R)={0,1,2,3,4,5,...}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Dom(R)={0,1,2,3,4,5,...}
The set of all non-negative integers is {0,1,2,3,4,5,...}

We denote this set by W.

The relation R in the set-builder form is,

R={(a,b)W×W:b=ak}

So, the domain is,

Dom(R)=W={0,1,2,3,4,5,...}

But, for each a in the domain W and for all positive integers k, the image of a under R, which is, R(a)=b=ak can take many values which can only be represented in set-builder form.

So, the range of the relation R is,

Range(R)={ak:aW,k>0}

And, the Codomain is,
W={0,1,2,3,4,5,...}

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Watch in App
Join BYJU'S Learning Program
CrossIcon