A remote-sensing satellite of earth revolves in a circular orbit at a height of 0-25 - 106 m above the surface of earth- If earth-s radius is 6-4 - 106 m and g -9-8 ms -2- then the orbital speed of the satellite isA- 6-67 kms -1B- 7-76 kms -1C- 8-56 kms -1D- 9-13 kms -1

The orbital velocity of the satellite is v=√(GMR+h) nbsp; where M= mass of earth and R= radius of earth. so, v=√(6.67× 10^ 11× (6× 10^24)(6.4× 10^6)+(0.25× 10 ...

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Standard XII

Physics

Centripetal Force

A remote-sens...

Question

A remote-sensing satellite of earth revolves in a circular orbit at a height of $0.25 \times 10^{6}$ $m$ above the surface of earth. If earth's radius is $6.4 \times 10^{6} m$ and $g = 9.8 m s^{- 2}$ , then the orbital speed of the satellite is

6.67 k m s^{- 1}

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7.76 k m s^{- 1}

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8.56 k m s^{- 1}

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9.13 k m s^{- 1}

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Solution

The correct option is B $7.76 k m s^{- 1}$
The orbital velocity of the satellite is $v = \sqrt{\frac{G M}{R + h}}$ where $M =$ mass of earth and $R =$ radius of earth.
so, $v = \sqrt{\frac{6.67 \times 10^{- 11} \times (6 \times 10^{24})}{(6.4 \times 10^{6}) + (0.25 \times 10^{6})}} = 7.76 k m / s$

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A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25×106 m above the surface of earth. If earth's radius is 6.4×106 m and g=9.8 ms−2, then the orbital speed of the satellite is

The correct option is B 7.76kms−1The orbital velocity of the satellite is v=√GMR+h where M= mass of earth and R= radius of earth. so, v= ⎷6.67×10−11×(6×1024)(6.4×106)+(0.25×106)=7.76 km/s

A remote-sensing satellite of earth revolves in a circular orbit at a height of $0.25 \times 10^{6}$ $m$ above the surface of earth. If earth's radius is $6.4 \times 10^{6} m$ and $g = 9.8 m s^{- 2}$ , then the orbital speed of the satellite is

The correct option is B $7.76 k m s^{- 1}$
The orbital velocity of the satellite is $v = \sqrt{\frac{G M}{R + h}}$ where $M =$ mass of earth and $R =$ radius of earth.
so, $v = \sqrt{\frac{6.67 \times 10^{- 11} \times (6 \times 10^{24})}{(6.4 \times 10^{6}) + (0.25 \times 10^{6})}} = 7.76 k m / s$