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Question

A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25×106 m above the surface of earth. If earth's radius is 6.4×106 m and g=9.8 ms2, then the orbital speed of the satellite is
  1. 6.67kms1
  2. 7.76kms1
  3. 8.56kms1
  4. 9.13kms1


Solution

The correct option is B 7.76kms1
The orbital velocity of the satellite is v=GMR+h  where M= mass of earth and R= radius of earth.
so, v= 6.67×1011×(6×1024)(6.4×106)+(0.25×106)=7.76 km/s 

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