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Standard X

Physics

Electric Power

A reservoir h...

Question

A reservoir had 186.55 tmc of water initially. Later 45.42 tmc of water was released to produce hydroelectic power. What was the remaining amount of water in the reservoir?

228.97 tmc

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41.13 tmc

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142.00 tmc

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141.13 tmc

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Solution

The correct option is D 141.13 tmc
Water stored in the reservoir = 186.55 tmc

Amount of water released = 45.42 tmc

Remaining water in the reservoir = 186.55 - 45.42

186.55
- 45.42
----------
141.13
----------

Hence, the remaining water in the reservoir 141.13 tmc.

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Q. A & B are two separate reservoirs of water. The capacity of reservoir A is double the capacity of reservoir B. Both the reservoirs are filled completely with water, their inlets are closed and then the water is released simultaneously from both the reservoirs. The rate of flow of water out of each reservoir at any instant of time is proportional to the quantity of water in the reservoir at that time. One hour after the water is released, the quantity of water in reservoir A is

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T = l o g_{4 / 3} n

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A

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B

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and

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where

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A reservoir had 186.55 tmc of water initially. Later 45.42 tmc of water was released to produce hydroelectic power. What was the remaining amount of water in the reservoir?

The correct option is D 141.13 tmcWater stored in the reservoir = 186.55 tmc Amount of water released = 45.42 tmc Remaining water in the reservoir = 186.55 - 45.42 186.55 - 45.42 ---------- 141.13 ---------- Hence, the remaining water in the reservoir 141.13 tmc.

The correct option is D 141.13 tmc
Water stored in the reservoir = 186.55 tmc

Amount of water released = 45.42 tmc

Remaining water in the reservoir = 186.55 - 45.42

186.55
- 45.42
----------
141.13
----------

Hence, the remaining water in the reservoir 141.13 tmc.