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Question

# A resistance-meter has five measurement range-settings between 200 Ω and 2 MΩ in multiples of 10. The meter measures resistance of a device by measuring the full-range voltage of 2 V across the device by passing an appropriate constant current for each range-setting. If a device having a resistance value in the range 8 kΩ to 12 kΩ and a maximum power rating of 100 μW is to be measured safely with this meter, the choice for range-setting on the meter for best resolution in measurement, in kΩ, is

A
2
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B
20
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C
200
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D
2000
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Solution

## The correct option is C 200 Resistance to be measured ⇒ 8 kΩ to 12 kΩ So, minimum range should be 20 kΩ. With 20 kΩ range: I=2V20kΩ=110mA Pmax=I2Rmax =(110×10−3)2×12×103 W =120 μW>100 μW With 200 kΩ range: I=2V200kΩ=1100mA Pmax=I2Rmax =(1100×10−3)2×12×103 W =1.2 μW

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