A resistance of $10 Ω$ and an inductance of $100 m H$ are connected in series with an AC source of voltage $V = 100 cos (100 t)$ volt. The phase difference between the voltage applied and the current flowing in the circuit will be

z e r o

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\frac{π}{2}

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\frac{π}{4}

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π

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Solution

The correct option is D $\frac{π}{4}$
In complex plane,
impedance of circuit $= Z = R + j L ω = 10 + 10 j = 10 \sqrt{2} ∠ π / 4$
voltage applied $= V = 100 ∠ 0$
current $= I = \frac{V}{Z} = \frac{100 ∠ 0}{10 \sqrt{2} ∠ π / 4} = \frac{10}{\sqrt{2}} ∠ - π / 4$
The phase difference between the voltage applied and the current flowing $= - \frac{π}{4}$ radians

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A resistance of 10 Ω and an inductance of 100 mH are connected in series with an AC source of voltage V=100cos(100t) volt. The phase difference between the voltage applied and the current flowing in the circuit will be

The correct option is D π4In complex plane,impedance of circuit=Z=R+jLω=10+10j=10√2∠π/4voltage applied =V=100∠0current=I=VZ=100∠010√2∠π/4=10√2∠−π/4The phase difference between the voltage applied and the current flowing=−π4radians

A resistance of $10 Ω$ and an inductance of $100 m H$ are connected in series with an AC source of voltage $V = 100 cos (100 t)$ volt. The phase difference between the voltage applied and the current flowing in the circuit will be