Question

A resistance of $12\Omega$ is connected in series with a resistance of $8\Omega$ . Difference of $20$ Volts is applied across the combination. What is the potential difference across the $12\Omega$ resistance?

• A. $8$ volts
• B. $10$ volts
• C. $12$ volts
• D. $20$ volts

Answer 1

The correct option is C $12$ volts

Resistance in series gets added up.

So, the equivalent resistance comes out to be equal to

$R_{eq}=R_1+R_2=12+8=20$

Current through the circuit is $I=\frac{V}{R_{eq}}$

$I=\frac{20}{20}=1A$

Voltage across $12\Omega$ resistance is $V_{12}=I\times R=12V$

Option C