A resistance of 20 ohms is connected to a source of an alternating potential V=220sin(100πt). The time taken by the current to change from its peak value to r.m.s value is
A
0.2sec
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B
0.25sec
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C
25×10−3sec
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D
2.5×10−3sec
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Solution
The correct option is D2.5×10−3sec Peak value to r.m.s. value means, current becomes 1√2 times. Sofromi=i0sin100πt⇒1√2×i0=i0sin100πt ⇒sinπ4=sin100πt⇒t=1400sec=2.5×10−3sec.