Question

A resistance of $300\Omega$ and an inductance of $\frac{1}{\pi }$ henry are connected in series to a ac voltage of 20 volts and 200 Hz frequency. The phase angle between the voltage and current is

• A. $ta{n}^{-1}\frac{4}{3}$
• B. $ta{n}^{-1}\frac{3}{4}$
• C. $ta{n}^{-1}\frac{3}{2}$
• D. $ta{n}^{-1}\frac{2}{5}$

Answer 1

The correct option is A $ta{n}^{-1}\frac{4}{3}$

Phase angle $tan\varphi =\frac{\omega L}{R}=\frac{2\pi \times 200}{300}\times \frac{1}{\pi }=\frac{4}{3}$
$\therefore \varphi =ta{n}^{-1}\frac{4}{3}$