A resistance of potentiometer wire of length 10m is 25 ohm. A resistance box and a 2 volt accumulator are connected in series with it. What resistance should be introduced from the resistance box to have potential drop of one microvolt per millimeter of the potentiometer wire

Open in App

Solution

Suggest Corrections

Similar questions

Q. A potentiometer wire of length

10 m

and resistance

10 Ω

per metre is connected in series with a resistance box and a

2 v o l t

battery. If a potential difference of

100 m V

is balanced across the whole length of potentiometer wire, then the resistance introduced in the resistance box will be:

Q. A potentiometer wire has a length of

10 m

and resistance

4 Ω m^{- 1}

. An accumulator of emf

2 V

and a resistance box are connected in series with it. Calculate the resistance to be introduced in the box to get a potential gradient of

0.1 V/m

Q. A potentiometer wire has length 4 m and resistance

8 Ω

. The resistance that must be connected in series with the wire and an accumulator of e.m.f 2V, so as to get a potential gradient 1 mV per cm on the wire is

A potentiometer wire has length $4$ m and resistance $8 Ω$ .What should be the resistance that must be connected in series with the wire and an accumulator of emf $2$ V, so as to get a potential gradient $1$ mV per cm on the wire?

Q. A cell of emf 2 V and negligible resistance is connected in series with a resistance of 5 ohm, and a potentiometer wire of resistance 10 ohm. The potential drop per cm if the length of the potentiometer wire is 10 m. The emf of cell which is balanced by 750 cm long wire is :

Join BYJU'S Learning Program