Question

A resistive transducer is used to measure quantity x is connected in the signal conditioning circuit as shown below. For $x=10$ , magnitude of sensitivity $\left(V_o/V_s\right)$ of the circuit is ?

• A. 6.66

Answer 1

The correct option is A 6.66
$\text{Using the superposition principle,}$

$\frac{V_o}{V_s}=\frac{2R}{3R}[1+\frac{2R(1+x)}{R}]-\frac{2R(1+x)}{R}$

$=\frac{2}{3}(3+2x)-2(1+x)$

$=(\frac{4}{3}-2)x=-\frac{2}{3}x$

$\therefore \frac{V_o}{V_x}=-\frac{2}{3}x$

$\text{For x = 10,}$

$\frac{V_o}{V_x}=\frac{2}{3}x=-\frac{2}{3}\times 10=6.66$

Since sensitivity has been asked so (-) sign is omitted.

$\pm 6.666=\pm 6.67$

However both the signs are accepted as answer.