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Question

A resistor develops 500J of thermal energy in 20s when a current of 1.5A is passed through it. If the current is increased from1.5A to 3A, what will be the energy developed in the 20s.


A

500J

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B

1000J

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C

2000J

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D

1500J

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Solution

The correct option is C

2000J


Step 1. Given Data,

Thermal energy of a resistor H1=500J

Time T=20s

Current I1=1.5A

Current I2=3A,

Let H2 be the energy developed in the 20s.

Step 2. Calculate the value of H2 energy developed in the 20s.

Using Joule's law of heating, H=I2RT

Thermal energy when a current I1=1.5Apassed through the rasistor,

H1=I12RT

Thermal energy when a current I2=3Apassed through the rasistor,

H2=I22RT

Keeping all other parameters same we are changing current from 1.5A to 3A.

Thus, H1H2=I1I22

H2=H1xI2I12H2=500x31.52H2=2000J

The value of H2 energy developed in the 20s is 2000J

Hence, option C is correct.


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