A resistor

has a resistance fo 176 ohms. How many of these resistors should be connected in parallel so that their combination draws a current of 5 amperes from a 220 volt supply line?

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Solution

For Resistors in Parallel,

1/R(total) = 1/R₁ + 1/R₂ + 1/Rₓ

From Ohm's Law

V = IR
220 = (5)R
R = 44 Ω

Therefore

1/44 = No. of 176Ω Resistors * 1/176

Let no. of 176Ω Resistors be x

Then 1/44 = x/176

x = 4

Therefore, 4 resistors of 176Ω ( in parallel) are required to carry 5 A on a 220 V line.

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