Question

A resistor has a resistance of $176\Omega$ . How many of these resistor has to be connected in parallel so that their combination draws a current of $5A$ from $220V$ supply line.

Answer 1

The resistances when connected in parallel is given as

$\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_N}$

We know that

$V=iR$

By substituting the values in above equation we get

$R=44\Omega$.

Let there are$N$number of resistors

Then,

$\frac{1}{44}=\frac{N}{176}$

We get the number of resistor is$4$