A resistor of 10 kΩ has a tolerance of 10% and another of 20 kΩ has a tolerance of 20%. The tolerance of the series combination is nearly
A
10%
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B
20%
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C
15%
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D
17%
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Solution
The correct option is D 17% r1=10kΩ,Δr1=10100×10=1kΩr2=20kΩ,Δr2=20100×20=4kΩ Maximum tolerance =Δr1+Δr2 =1+4=5 r1+r2=10+20=30kΩ % age of tolerance =530×100 =16.67 % =17 %