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Question

# A resistor of 4-ohm resistance and an electric lamp of 20-ohm resistance are connected in series across a 6-volt battery. Draw a labelled circuit diagram by using the symbols for ohm and volt. Calculate: (a) total resistance of the circuit. (b) current flowing through the circuit. (c) potential difference across the resistor. ​(d) potential difference across the electric lamp.

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Solution

## (a) 4-ohm resistance and 20-ohm lamp are connected in series. Hence, the total resistance of the circuit = $4\mathrm{\Omega }+20\mathrm{\Omega }=24\mathrm{\Omega }$ (b) Current flowing in the circuit = $\frac{\mathrm{Voltage}}{\mathrm{Total}\mathrm{resistance}}=\frac{6\mathrm{V}}{24\mathrm{\Omega }}=0.25\mathrm{A}$ (c) The potential difference across the resistor = Current through the resistor $×$ Resistance = $0.25\mathrm{A}×4\mathrm{\Omega }=1\mathrm{V}$ (d) The potential difference across the lamp = Current through the lamp $×$ Resistance = $0.25\mathrm{A}×20\mathrm{\Omega }=5\mathrm{V}$

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