Question

A resistor of $6k\Omega$ with tolerance $10\%$ and another of $4k\Omega$ with tolerance $10\%$ are connected in series.The tolerance of combination is about

• A. $5\%$
• B. $10\%$
• C. $12\%$
• D. $15\%$

Answer 1

The correct option is B $10\%$

In series combination,
$R=R_1+R_2=6+4=10k\Omega$
Error in combination
$\Delta R=\Delta R_1+\Delta R_2$
$\frac{10}{100}\times 6+\frac{10}{100}\times 4$
$=0.6+0.4=1$
$\therefore \frac{\Delta R}{R}=\frac{1}{10}=10\%$