Question

A resistor of $6\Omega$ is connected in series with another resistor of $4\Omega$. A potential difference of 20 V is applied across the combination. Calculate:

(a) the current in the circuit, and

(b) the potential difference across the $6\Omega$ resistor.

Answer 1

(a)

$R_{eq}=6+4=10\Omega$

Current, $I=\frac{V}{R_{eq}}=\frac{20}{10}=2A$

(b) Potentail difference across the $6\Omega$ resistor $=IR=2\times 6=12V$