A resistor of R - 6- an inductor of L - 1 H and a capacitor of C - 17-36- F are connected in series with an AC source- Find the Q-factor-

The correct option is B 40 Q factor = 1R√(LC) = 16√(117.36× 10^ 6) = 40 . ...

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Byju's Answer

Standard XII

Physics

Power Factor

A resistor of...

Question

A resistor of $R = 6 Ω$ , an inductor of $L = 1 H$ and a capacitor of $C = 17.36 μ F$ are connected in series with an AC source. Find the Q-factor.

3.72

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40

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2.37

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80

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Solution

The correct option is B $40$
$Q - f a c t o r = \frac{1}{R} \sqrt{\frac{L}{C}}$
$= \frac{1}{6} \sqrt{\frac{1}{17.36 \times 10^{- 6}}} = 40$ .

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A resistor of R=6Ω, an inductor of L=1 H and a capacitor of C=17.36μF are connected in series with an AC source. Find the Q-factor.

The correct option is B 40Q−factor=1R√LC=16√117.36×10−6=40.

A resistor of $R = 6 Ω$ , an inductor of $L = 1 H$ and a capacitor of $C = 17.36 μ F$ are connected in series with an AC source. Find the Q-factor.

The correct option is B $40$
$Q - f a c t o r = \frac{1}{R} \sqrt{\frac{L}{C}}$
$= \frac{1}{6} \sqrt{\frac{1}{17.36 \times 10^{- 6}}} = 40$ .