A resistor of resistance 30Ω, inductor of reactance 10Ω and capacitor of reactance 10Ω are connected in series to an ac voltage source ϵ=300√2sinωt. The current in the circuit is
A
10√2A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
10A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
30√11A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
30√11A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A10√2A Z=√R2+(XL−Xc)2Z=√302Z=30Vs=300√2I=VsZ=10√2