A resistor R has power dissipation P with cell voltage E. The resistor is cut in n equal parts and all parts are connected in parallel with same cell. The new power dissipation is:
A
nP
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B
nP2
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C
n2P
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D
nP
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Solution
The correct option is Cn2P Resistance of each part =Rn Effective resistance =Rn2 Battery voltage is constant P∝1R⇒P′P=PR/n2=n2