A resonance tube of length 1 m is resonated with a tuning fork of frequency 300 Hz. If the velocity of sound in air is 300ms−1 then the number of harmonics produced in the tube will be
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is A 2 From the formula , v=fλ , we get ,
λ=v/f=300/300=1m ,
let the lengths of resonant columns be l1,l and l3 , therefore
for first resonance ,
l1=λ/4=1/4=0.25m ,
for second resonance ,
l2=3λ/4=1/4=0.75m ,
for third resonance ,
l3=5λ/4=1/4=1.25m ,
it is clear that only two harmonics are possible , because l3 is greater than total length 1m of tube .