CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A resonance tube of length 1 m is resonated with a tuning fork of frequency 300 Hz. If the velocity of sound in air is 300ms1 then the number of harmonics produced in the tube will be

A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2
From the formula , v=fλ , we get ,
λ=v/f=300/300=1m ,
let the lengths of resonant columns be l1,l and l3 , therefore
for first resonance ,
l1=λ/4=1/4=0.25m ,
for second resonance ,
l2=3λ/4=1/4=0.75m ,
for third resonance ,
l3=5λ/4=1/4=1.25m ,
it is clear that only two harmonics are possible , because l3 is greater than total length 1m of tube .

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Standing Longitudinal Waves
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon