A resonant A.C. circuit contains a capacitor of capacitance $10^{- 6}$ F and an inductor of $10^{- 4}$ H. The frequency of oscillations will be :

10^{5}

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10 Hz

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\frac{10^{5}}{2 π}

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\frac{10}{2 π}

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Solution

The correct option is C $\frac{10^{5}}{2 π}$ Hz
$ω = \frac{1}{\sqrt{L C}}$
$⟹ f = \frac{1}{2 π \sqrt{L C}} = \frac{1}{2 π \times 10^{- 5}}$
$f = \frac{10^{5}}{2 π} H z$

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A resonant A.C. circuit contains a capacitor of capacitance 10−6 F and an inductor of 10−4 H. The frequency of oscillations will be :

The correct option is C 1052π Hzω=1√LC⟹f=12π√LC=12π×10−5f=1052πHz

A resonant A.C. circuit contains a capacitor of capacitance $10^{- 6}$ F and an inductor of $10^{- 4}$ H. The frequency of oscillations will be :

The correct option is C $\frac{10^{5}}{2 π}$ Hz
$ω = \frac{1}{\sqrt{L C}}$
$⟹ f = \frac{1}{2 π \sqrt{L C}} = \frac{1}{2 π \times 10^{- 5}}$
$f = \frac{10^{5}}{2 π} H z$