Question

A rhombus has diagonals that measure 6 cm and 8 cm. What is its area? How much does each side measure?

Answer 1

The Diagonals of rhombus is $6,8$cm

The area of rhombus is given as $\frac{1}{2}\times 6\times 8$

Thus required area of rhombus is $24$ $c{m}^2$

The diagonals of the rhombus bisect each other at right angles

So the sides of right triangle formed by diagonals and sides are $3,4$

So by pythagoras theorem

$Sid{e}^2=3^2+4^{2}sid{e}^2=16+9sid{e}^2=25side=\sqrt{25}Side=5$

Hence length of side is $5$ $cm$