A rhombus has the sum of it's diagonals equal to $34$ cm. Its longer diagonal is $14$ cm longer than its shorter diagonal. Find its area (in $c m^{2}$ )

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

120

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

135

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $120$
Given, $D i a g o n a l_{1} + D i a g o n a l_{2} = 34 c m$
But $D i a g o n a l_{1} = 14 + D i a g o n a l_{2}$

So,
$14 + D i a g o n a l_{2} + D i a g o n a l_{2} = 34 c m$
$=> 2 D i a g o n a l_{2} = 20 c m$
$=> D i a g o n a l_{2} = 10 c m$

And $D i a g o n a l_{1} = 14 + 10 = 24 c m$

Area of a rhombus $= \frac{1}{2} \times (D i a g o n a l_{1} \times D i a g o n a l_{2}) = \frac{1}{2} \times (24 \times 10) = 120 c m^{2}$

Suggest Corrections

Similar questions

c m^{2}

850

{cm}^{2}

34

20

10

12

c m^{2}

Join BYJU'S Learning Program