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# A Rhombus of side of 10cm has two angles of 60o each. Find the length of diagonals and also find its area. A
The length of diagonals AC=203cm and BD=10cm
Area of Rhombus =353sq.cm
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B
The length of diagonals AC=103cm and BD=10cm
Area of Rhombus =503sq.cm
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C
The length of diagonals AC=163cm and BD=10cm
Area of Rhombus =203sq.cm
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D
The length of diagonals AC=193cm and BD=10cm
Area of Rhombus =303sq.cm
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Solution

## The correct option is B The length of diagonals AC=10√3cm and BD=10cmArea of Rhombus =50√3sq.cmLet ABCD be a rhombus of side 10cm and ∠BAD=∠BCD=60o. Diagonals of parallelogram bisect each other.So, AO=OC and BO=ODIn right triangle AOBsin30o=OBAB⇒ 12=OB10⇒ OB=5cm∴ BD=2(OB)⇒ BD=2(5)⇒ BD=10cmcos30o=OAAB⇒ √32=OA10⇒ OA=5√3∴ AC=2(OA)⇒ AC=2(5√3)⇒ AC=10√3cmSo, the length of diagonals AC=10√3cm and BD=10cmArea of Rhombus =12×AC×BD=12×10√3×10=50√3   Suggest Corrections  0      Similar questions  Related Videos   Rhombus
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