Let ABCD be a rhombus-shaped field.
For ΔBCD,
Semi-perimeter, s=(48+30+30)2=54m
By Heron's formula,
Area of triangle = √s(s−a)(s−b)(s−c)
Therefore the area of
ΔBCD=⌊√54(54−48)(54−30)(54−30)⌋m2=√54(6)(24)(24)=432m2
Area of field = 2 × Area of ΔBCD
=(2×432)m2=864m2
Area of grazing for 1cow = 86418=48m2
Each cow will get 48 m2 area of grassfield.