A rifle resting against a cushion fires a bullet as shown. Figure (a) below shows the event before firing the bullet. After firing the bullet, the rifle compresses the cushion by 25mm and comes to rest.
A
The change in momentum of the bullet is 14.7kgm/s.
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B
The recoil speed of the rifle immediately after firing 3.5m/s.
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C
The average force exerted by the cushion in stopping the rifle is 1.03kN.
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D
Work done by the rifle on the bullet is 25.73J
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Solution
The correct option is D Work done by the rifle on the bullet is 25.73J Change in momentum, Δ→pb=mΔ→vb=0.0525(280−0)=14.7kgm/s 4.20×vr=14.7 ⇒vr=3.5m/s
Work done by Fav = Change in kinetic energy of the rifle. Fav×0.025=12×4.20×3.52=25.73J Fav≈1.03×103N