Question

A right-angle triangle has an area of $8c{m}^2$ and a height of $2\sqrt{2}$ cm. Find the length of its base.

• A. $\sqrt{32}cm$
• B. $\sqrt{16}cm$
• C. $\sqrt{48}cm$
• D. $\sqrt{24}cm$

Answer 1

The correct option is A $\sqrt{32}cm$

Let $ABC$ be the right angled triangle where $AB=$ height and $BC=$ base.
Area $=\frac{AB\times BC}{2}$
$BC=l$ and $AB=2\sqrt{2}$
$8=\frac{l\left(2\sqrt{2}\right)}{2}$
$l=\sqrt{32}$

Hence, the answer is $\sqrt{32}$.