A right angle triangle of base 4 cm and height 3 cm is revolved about its height. The surface area and volume of obtained solid figure are respectively.

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Solution

As we revolve a right angle triangle about its height we will get a cone.

Surface area of cone = $π$ rl= $π$ $\times$ 4 $\times$ 5 = 20 $π$

Volume of the cone = $\frac{1}{3}$ $π$ $r^{2}$ h= $\frac{1}{3}$ $\times$ $π$ $\times$ 16 $\times$ 3 = 16 $π$

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A right angle triangle of base 4 cm and height 3 cm is revolved about its height. The surface area and volume of obtained solid figure are respectively.

As we revolve a right angle triangle about its height we will get a cone. Surface area of cone = πrl= π × 4 × 5 = 20 π Volume of the cone = 13πr2h=13 × π × 16 × 3 = 16 π

As we revolve a right angle triangle about its height we will get a cone.

Surface area of cone = $π$ rl= $π$ $\times$ 4 $\times$ 5 = 20 $π$

Volume of the cone = $\frac{1}{3}$ $π$ $r^{2}$ h= $\frac{1}{3}$ $\times$ $π$ $\times$ 16 $\times$ 3 = 16 $π$