Question

A right angled triangle has the largest side as $13cm$ and one of the sides containing the right angle as $12cm.$ Its area in ${cm}^2$ is

Answer 1

$△ABC$ using Pythagoras therm ---

$A{C}^2=A{B}^2+B{C}^2$

$A{B}^2=A{C}^2-B{C}^2$

$=(13{)}^2-(12{)}^2$

$=169-144$

$A{B}^2=25$

$AB=5$

Area of triangle = $\frac{1}{2}\times base\times Height$

$=\frac{1}{2}\times 5\times 12$

$=30c{m}^2$