A right circular cone of height h is cut by a plane parallel to the base at a distance h-3 from the base- then the volumes of the resulting cone and the frustum are in the ratio -

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Solid Geometry

A right circu...

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A right circular cone of height h is cut by a plane parallel to the base at a distance $\frac{h}{3}$ from the base, then the volumes of the resulting cone and the frustum are in the ratio :

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The radius of the base of a right circular cone is r. It is cut by a plane parallel to the base at a height h from the base.

The slant height of the frustum is $\sqrt{h^{2} + \frac{4}{9} r^{2}}$ . Show that the volume of the frustum is $\frac{13}{27} π r^{2} h$

\sqrt{h^{2} + \frac{9 r^{2}}{16}},

r

h

\sqrt{h^{2} + \frac{r^{2}}{9}}

\frac{13}{27} π r^{2} h

10

8

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