Question

A right circular cylinder has a radius of 14 cm and height 42 cm with both upper and lower circular areas closed. The total surface area of the cylinder is equal to ____.

• A. $4928{\text{cm}}^2$
• B. $4828{\text{cm}}^2$
• C. $4938{\text{cm}}^2$
• D. $4988{\text{cm}}^2$

Answer 1

The correct option is A

$4928{\text{cm}}^2$

Given: r = 14 cm ; h = 42 cm

Total Surface Area of a Cylinder
$=\text{Curved surface area}+2\times BaseArea$

$=2\pi rh+2\pi r^2$

$=2\pi r(h+r)$

$=2\times \frac{22}{7}\times 14\times (42+14)$

$=2\times 22\times 2\times 56$

$=4928{\text{cm}}^2$

Hence, the total surface area of the cylinder $=4928{\text{cm}}^2$