A right cylinderical vessel is full of water. How many right cones having the same radius and height as those of the right cylinder will be needed to store that water?

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Solution

Volume of the cylinder of radius R and height H =πR²H
Volume of right cone of radius R and height H =⅓πR²H
Hence Number of right cones needed = $\frac{π R ² H}{⅓ π R ² H}$ =3

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A right cylinderical vessel is full of water. How many right cones having the same radius and height as those of the right cylinder will be needed to store that water?

Volume of the cylinder of radius R and height H =πR²H Volume of right cone of radius R and height H =⅓πR²H Hence Number of right cones needed =πR²H⅓πR²H =3

Volume of the cylinder of radius R and height H =πR²H
Volume of right cone of radius R and height H =⅓πR²H
Hence Number of right cones needed = $\frac{π R ² H}{⅓ π R ² H}$ =3