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Arrhenius Equation

A → B KA ...

Question

$A \to B K_{A} = 10^{15} e^{2000 / T}$

$C \to D K_{C} = 10^{14} e^{1000 / T}$

Temperature T K at which $(K_{A} = K_{C})$ is :

A

1000 K

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B

2000 K

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C

(2000 / 2.303) K

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D

(1000 / 2.303) K

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Solution

The correct option is D (1000 / 2.303) K
$A \to B K_{A} = 10^{15} e^{2000 / T} C \to D K_{C} = 10^{14} e^{1000 / T} A t T (K_{A} = K_{C}) C_{0}^{15} e^{2000 / T} = 10^{14} e^{1000 / T} 10 e^{2000 / T} = e^{1000 / T} 10 = e^{1000 / T} l o g_{e} 10 = 1000 / T T = \frac{1000}{l o g_{e} 10} T = (\frac{1000}{2.303}) k$

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Similar questions

A \to B K_{A} = 10^{15} e^{2000 / T} C \to D K_{C} = 10^{14} e^{1000 / T}

T (K)

(K_{A} = K_{C})

A \to B; K_{A} = 10^{15} e^{\frac{- 2000}{T}}

C \to D; K_{C} = 10^{14} e^{\frac{- 1000}{T}}

Temperature T in terms of K at which

K_{A} = K_{C}

Q. The rate constants

K_{1}

K_{2}

for two different reactions are

10^{15} e^{- \frac{1000}{T}}

10^{16} e^{- \frac{2000}{T}}

respectively. The temperature at which

K_{1} = K_{2}

Q. Vant' Hoff equation shows the effect of temperature on equilibrium constants

K_{c}

K_{p} .

K_{p}

varies with temperature according to the relation:

If [A] is the concentration of reactant A at any time t and [A_o] is the concentration at t=0, then for the first order reaction the rate equation can be written as:

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