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Question

# A rigid ball of mass m strikes a wall at 60∘ and gets reflected without loss of speed as shown in figure. The value of impulse imparted by the wall on the ball will be:

A
mv
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B
2 mv
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C
mv2
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D
mv3
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Solution

## The correct option is A mvThe component of velocity has changed along x−direction as shown in figure, hence momentum of ball has changed along the x− direction after receiving impulse from the wall. ⇒Net impulse in x- direction=ΔPx Jx=(Px)f−(Px)i=(mvcos60∘ ^i)−(−mvcos60∘ ^i) ⇒Jx=2mvcos60∘ ^i=2mv×12^i=mv ^i ∴|Jx|=mv Hence wall has exerted impulse of value mv in a direction normal to wall.

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