Question

A rigid link PQ of length 2 m rotates about the pinned end Q with a constant angular acceleration of 12 rad/s${}^2$. When the angular velocity of the link is 4 rad/s, the magnitude of the resultant acceleration (in m/s${}^2$of the end P is

Answer 1

$a_r=r\alpha =2\times 12=24m/s^2$
$a_R={\omega }^{2}r=16\times 2=32m/s^2$
$a=\sqrt{a_T^2+a_R^2}=\sqrt{{24}^2+{32}^2}$
$=\sqrt{1600}=40m/s^2$