The correct options are
A Sector BOC has greater kinetic energy than sector COD with respect to ground
C Sector ABC has greater kinetic energy than sector ADC with respect to ground
D Sector BOC has same kinetic energy as sector AOB with respect to ground
Let 'dm' be the small particlesK.E. = 12(dm)v2
∴vnet=√v2+w2R2+2vwRcosθ
In section ABC we have (θ<90o)
∴vnet will greater w(cosθ) have positive value.
In section ADC we have (θ>90o)
∴vnet will decrease w(cosθ) have negative value
⇒ We can say that,
(K.E.)ABC>(K.E.)ADC
As in sector BOC θ<90o and in sector CODθ>90o
∴(K.E.)BOC>(K.E.)COD
As in sector AOB and BOC, θ<90o
∴(K.E.)AOB=(K.E)BOC
∴ the correct option is,
A) Sector BOC has greater kinetic energy than sector COD with respect to ground.
B) Sector ABC has greater kinetic energy than sector ADC.
C) Sector BOC has same kinetic energy as sector AOB.
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