A ring having radius $2.5 cm$ and mass $10 gram$ floats on a liquid surface having surface tension $0.06 N/m$ . Find force required to just lift the ring from liquid surface.

0.06 N

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0.12 N

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0.24 N

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0.03 N

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Solution

The correct option is B $0.12 N$
As inner and outer surface of ring are in contact with water surface
$F = 4 π r T + M g$
$= 4 \times 3.14 \times (2.5 \times 10^{- 2}) \times 0.06 + (10 \times 10^{- 3}) \times 9.8$
$= 0.01884 + 0.098 = 0.12 N$

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A ring having radius 2.5 cm and mass 10 gram floats on a liquid surface having surface tension 0.06 N/m. Find force required to just lift the ring from liquid surface.

The correct option is B 0.12 NAs inner and outer surface of ring are in contact with water surface F=4πrT+Mg =4×3.14×(2.5×10−2)×0.06+(10×10−3)×9.8 =0.01884+0.098=0.12 N

A ring having radius $2.5 cm$ and mass $10 gram$ floats on a liquid surface having surface tension $0.06 N/m$ . Find force required to just lift the ring from liquid surface.

The correct option is B $0.12 N$
As inner and outer surface of ring are in contact with water surface
$F = 4 π r T + M g$
$= 4 \times 3.14 \times (2.5 \times 10^{- 2}) \times 0.06 + (10 \times 10^{- 3}) \times 9.8$
$= 0.01884 + 0.098 = 0.12 N$