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Question
A ring of diameter lm is rotating with an angular momentum of 10 Joules-sec. The necessary tangential force required to increase its angular momentum by 50% in sec will be (in newtons)-
A ring of diameter lm is rotating with an angular momentum of 10 Joules-sec. The necessary tangential force required to increase its angular momentum by 50% in sec will be (in newtons)-
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Solution
The correct option is A 10
L
= 10 J s. dL = 10/2 J-s
Assume
that the ring is rotating around the axis through its center.
Torque
= F * R = dL/ dt
F
* 1/2 m = 5 J-s / 1 s
F
= 10 N
L = 10 J s. dL = 10/2 J-s
Assume that the ring is rotating around the axis through its center.
Torque = F * R = dL/ dt
F * 1/2 m = 5 J-s / 1 s
F = 10 N
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