A ring of mass 10kg and diameter 0.4m is rotating about its geometrical axis at 1200 rotations/minute. Its moment of inertia and angular momentum will be respectively:
A
0.4kgm2 and 50.28Joule/sec
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B
50.28kgm2 and 0.4Joule/sec
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C
0.4Joule/sec and 50.28kgm2
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D
0.4kgm2 and 0kgm2
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Solution
The correct option is A0.4kgm2 and 50.28Joule/sec Moment of Inertia, I=Mr2=10×0.22=0.4kgm2 Angular Momentum, L=I×ω=0.4×(1200×2π60)=50.28Joule/sec