A ring of mass m and radius R is rolling down a rough inclined plane of angle θ with horizontal. Plot the angular momentum of the ring about the point of contact of ring and the plane as a function of time:
A
Diagram
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Diagram
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Diagram
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Diagram
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A Diagram Torque about point of contact of the ring,
τ=(mgsinθ)R
We know that,
τ=ΔLΔt
From this, L=(Δt)τ
Therefore, the curve between L and time t will be straight line.