Question

A ring of mass $m$ and radius $R$ is rolling down a rough inclined plane of angle $\theta$ with horizontal. Plot the angular momentum of the ring about the point of contact of ring and the plane as a function of time:

• A. Diagram
• B. Diagram
• C. Diagram
• D. Diagram

Answer 1

The correct option is A Diagram

Torque about point of contact of the ring,

$\tau =\left(mg\sin \theta \right)R$

We know that,

$\tau =\frac{\Delta L}{\Delta t}$

From this, $L=\left(\Delta t\right)\tau$

Therefore, the curve between $L$ and time $t$ will be straight line.