wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ring of mass m and radius R rotates about an axis passing through its centre and perpendicular to its plane with angular velocity ω. Find the velocity of transverse pulse in the ring.

A
Rω2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2Rω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
32Rω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Rω
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Rω
Let T be the tension produce in the ring.
Take a elementary part of ring having mass dm, subtending an angle dθ at centre


Here, T sin (dθ2)+T sin (dθ2)=2T sin (dθ2) will be responsible for coertripetal force
So 2T sin(dθ2)=dmRω2
2Tdθ2=m2πRRdθ.Rω2
T=mRω22π
and μ=m2πR
[dθ2is very small and dm=m2πRRdθ]
So, velocity of transverse pulse
v=Tμ=     (mRω22π)(m2πR)=Rω

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon