A ring of radius 100 cm has a uniformly distributed charge Q and uniformly distributed mass m. On the axis a point charge –Q of mass 2m is placed at a distance 3 cm form its centre. Both are released from rest. Assuming only electric interaction between the ring and particle, find the amplitude (in cm) of SHM of particle.___

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Solution

Since there is no external force, CM will remain at rest. Displacement of the particle till it comes to the centre of the ring is given by

$x = 3 \times \frac{m}{m + 2 m} = 1 c m ∴ A = 1 c m$

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Since there is no external force, CM will remain at rest. Displacement of the particle till it comes to the centre of the ring is given by x=3×mm+2m=1cm∴A=1cm

Since there is no external force, CM will remain at rest. Displacement of the particle till it comes to the centre of the ring is given by

$x = 3 \times \frac{m}{m + 2 m} = 1 c m ∴ A = 1 c m$