A ring of radius 1m has moment of inertia of 10kg−m2 about an axis through its centre and perpendicular to its plane. If a constant force of 50N is applied to it tangentially as shown, what will be its angular acceleration?
A
5rad/s2
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B
10rad/s2
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C
2.5rad/s2
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D
πrad/s2
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Solution
The correct option is A5rad/s2 This Force will produce torque on this ring as discussed by Aanand in the previous video clip.
Given,I=10kg−m2
r = 1m
F = 50N |→τ|=rFsinθ=rFsin90o
= r F = 50 N-m
Recall, |→τ|=I|→α| |→α|=|→τ|I=5010=5rads2