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Question

A ring of radius 1m has moment of inertia of 10kgm2 about an axis through its centre and perpendicular to its plane. If a constant force of 50N is applied to it tangentially as shown, what will be its angular acceleration?

A
5 rad/s2
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B
10 rad/s2
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C
2.5 rad/s2
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D
π rad/s2
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Solution

The correct option is A 5 rad/s2
This Force will produce torque on this ring as discussed by Aanand in the previous video clip.
Given,I=10kgm2
r = 1m
F = 50N
|τ|=r F sin θ = r F sin 90o
= r F = 50 N-m
Recall, |τ|=I|α|
|α|=|τ|I=5010=5rads2

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